Q.
Coefficient of the constant term in the expansion of E=x2/3+4x1/3+451x1/3−1+1x2/3+x1/3+1−9is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
74
b
98
c
148
d
168
answer is D.
(Unlock A.I Detailed Solution for FREE)
Detailed Solution
E=x1/3+225x2/3+x1/3+1+x1/3−1x−1−9 =2+x1/310x2/3+2x1/3x−1−9 =2+x1/310(x−1)9x1/39x1/3+29 =2+x1/3x−3(x−1)9Constant term in E =2[constant term in x−3(x−1)9 =2(-1)9 [ coefficient of x3 in 1-x9] =2(−1)9C3(−1)=168
Watch 3-min video & get full concept clarity