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Q.

Coefficient of the constant term in the expansion of E=x2/3+4x1/3+451x1/3−1+1x2/3+x1/3+1−9is

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a

74

b

98

c

148

d

168

answer is D.

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Detailed Solution

E=x1/3+225x2/3+x1/3+1+x1/3−1x−1−9   =2+x1/310x2/3+2x1/3x−1−9  =2+x1/310(x−1)9x1/39x1/3+29   =2+x1/3x−3(x−1)9Constant term in E                     =2[constant term in x−3(x−1)9                     =2(-1)9 [ coefficient of x3 in 1-x9]                     =2(−1)9C3(−1)=168
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