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Coefficient of constant term in the expansion of
is
detailed solution
Correct option is D
Let y=3−log3x3/2⇒log3 y=−log3 x3/2log3 3=−2log3 x3/2⇒y=x−3(r + 1)th term in the expansion of x3+5x−34 is Tr+1=4Crx34−r5x−3r=4Cr5rx12−3r−3rFor (r + 1)th term to be independent of x, set 12 – 6r=0 or r=2∴ required constant term=4C252=(6)(25)=150Talk to our academic expert!
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If the coefficients of P th, ( p + 1)th and (p + 2)th terms in the expansion of (1 + x)n are in AP, then
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