Download the app

Questions  

Coefficient of the term independent of x in the expansion of x+1x2/3x1/3+1x1xx1/210is

a
210
b
105
c
70
d
35

detailed solution

Correct option is A

We havex+1=x1/33+1=x1/3+1x2/3−x1/3+1,x−1=(x−1)(x+1)and x−x1/2=x(x−1),Thus,   x+1x2/3−x1/3+1−x−1x−x1/2         =x1/3+1−1+x−1/2=x1/3−x−1/2Now, the (r+1)th term in the expansion of x1/3−x−1/210 is    Tr+1=10Crx1/310−rx−1/2r(−1)r=10Crx103−5r/6(−1)rFor this term to be independent of x,                       103−5r6=0 ⇒ r=103×65=4 Thus, coefficient of the term independent of x in the given expression is                    10C4=10!4!6!=210.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

lf the term independent of x in the expansion of 32x213x9is k, then 18k is equal to


phone icon
whats app icon