The coefficient of x9 in the expansion of E =(1+x)9 +(1+x)10+…+(1+x)100 is
101C9
101C10
100C9
100C10
E=(1+x)9(1+x)92−11+x−1=(1+x)101−(1+x)9xCoefficient of x9 in E =coefficient of x10 in (1+x)101−(1+x)9 =101C10