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The coefficient of $x^{9}$ in the expansion of $E$ $= (1 + x)^{9^{}} + (1 + x)^{10} + \dots + (1 + x)^{100}$ is

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Correct option is B

E=(1+x)9(1+x)92−11+x−1=(1+x)101−(1+x)9xCoefficient of x9 in E =coefficient of x10 in (1+x)101−(1+x)9 =101C10

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The coefficient of x9 in the expansion of E =(1+x)9 +(1+x)10+…+(1+x)100 is

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The coefficient of $x^{9}$ in the expansion of $E$ $= (1 + x)^{9^{}} + (1 + x)^{10} + \dots + (1 + x)^{100}$ is