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Questions  

The coefficient of x53 in the expansion m=0100100Cm(x3)100m2m is 

a
100C47
b
100C53
c
−100C53
d
100C100

detailed solution

Correct option is C

The given sigma is the expansion of [(x−3)+2]100=(x−1)100=(1−x)100Therefore, x53 will occur in T54.T54=100C53(−x)53Therefore, the coefficient is -100C53

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