The coefficient of x53 in the expansion ∑m=0100 100Cm(x−3)100−m 2m is
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a
100C47
b
100C53
c
−100C53
d
−100C100
answer is C.
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Detailed Solution
The given sigma is the expansion of[(x−3)+2]100=(x−1)100=(1−x)100Therefore, x53 will occur in T54.T54=100C53(−x)53Therefore, the coefficient is −100C53.