First slide
Binomial theorem for positive integral Index
Question

The coefficient of x5 in the expansion of (1+2x)6(1x)7 is 

Moderate
Solution

(1+2x)6(1x)7=1+6C1(2x)+6C2(2x)2+6C3(2x)3+6C4(2x)4+6C5(2x)5+6C6(2x)6×17C1x+7C2x27C3x3+7C4x4

=1+12x+60x2+160x3+240x4+192x5+×17x+21x235x3+35x421x5+

 Coefficient of x5 in the expansion of (1+2x)6(1x)7

=1×(21)+12×35+60×(35) +160×21+240×(7)+192

=21+4202100+33601680+192

=171

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