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$Coefficient of x^{3} in the expansion {(x + \frac{1}{x^{2}})}^{6} is equal to$

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Correct option is C

Given binomial expansion is , x+1x26 The general term of the above expansion is x+1x26 Tr+1=Cr nxn-rar=Cr 6x6-r1x2r =Cr 6x6-rx-2r=Cr 6x6-3r To get coefficient of x3 equate the abvoe exponent of x to 6 we get, 6-3r=3⇒r=1 ∴T2=C1 6

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Coefficient of x3 in the expansion x+1x26is equal to

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$Coefficient of x^{3} in the expansion {(x + \frac{1}{x^{2}})}^{6} is equal to$