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Questions  

The coefficient of x28in the expansion of 1+x3x63nis 

a
1
b
0
c
30C6
d
30C3

detailed solution

Correct option is B

(1+x3−x630      =1+x31−x330       =30C0+30C1x31−x3+30C2x61−x32+…Obviously, each term will contain x3m,m∈N. But 28 is not divisible by 3. Therefore, there will be no term containing x28.

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