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Q.

The coefficient of x28in the expansion of 1+x3−x63nis

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a

1

b

0

c

30C6

d

30C3

answer is B.

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Detailed Solution

(1+x3−x630 =1+x31−x330 =30C0+30C1x31−x3+30C2x61−x32+…Obviously, each term will contain x3m,m∈N. But 28 is not divisible by 3. Therefore, there will be no term containing x28.

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