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Binomial theorem for positive integral Index

Question

The coefficient of   x7 in the expansion of 1xx2+x36is

Moderate
Solution

1xx2+x36=(1x)61x26

coefficient of x7 in  16C1x+6C2x2+6C6x6

= coefficient of in 16C1x+6C2x2+6C6x6×16C1x2+6C2x4+6C6x12

              

=6C16C3+6C3 6C2+6C56C1=144



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The coefficient of x7 in the expression (1+x)10+x(1+x)9+x2(1+x)8++x10 is


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