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Questions  

The coefficient of x in the expansion of 13x+7x2(1x)16 is 

a
19
b
-19
c
18
d
-18

detailed solution

Correct option is B

1−3x+7x2(1−x)16 =1−3x+7x2 16C0−16C1x+16C2x2+…After multiplying, the term containing x is  16C1x−3x16C0x ∴ Coefficient of x=−16−3=−19

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