First slide
Binomial theorem for positive integral Index
Question

The coefficient of x5 in the expansion of (1+x)21+(1+x)22++(1+x)30 is 

Moderate
Solution

(1+x)21+(1+x)22++(1+x)30

=(1+x)211+(1+x)1++(1+x)9=(1+x)21(1+x)101(1+x)1=1x(1+x)31(1+x)21

 Coefficient of f in the given expression

= Coefficient of x5 in 1x(1+x)31(1+x)21= Coefficient of x6 in (1+x)31(1+x)21=31C621C6

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