Q.
The coefficient of x101in the expansion of (1+x)300+x(1+x)299+x2(1+x)298+....+x300 is
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a
301C 100
b
300C 101
c
301C 99
d
301C 101
answer is D.
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Detailed Solution
(1+x)300+x(1+x)299+x2(1+x)298+….+x300(1+x)3001+x1+x+x2(1+x)2+….x1+x300=(1+x)3001−x1+x3011−x1+x=(1+x)300(1+x)301−x301(1+x)30111+x=(1+x)301−x301∴ The coefficient of x101 is 301C101
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