The coefficient of xk in the expansion of E=1+(1+x)+(1+x)2+…+(1+x)n is
nCk
n+1Ck
n+1Ck+1
none of these
We have E=1+(1+x)+(1+x)2+…+(1+x)n =1−(1+x)n+11−(1+x)=1x(1+x)n+1−1Thus, coefficient of xk in E = Coefficient of xk+1 in (1+x)n+1−1 =n+1Ck+1