First slide
Binomial theorem for positive integral Index
Question

The coefficient of xk in the expansion of E=1+(1+x)+(1+x)2++(1+x)n is

Moderate
Solution

We have
          E=1+(1+x)+(1+x)2++(1+x)n    =1(1+x)n+11(1+x)=1x(1+x)n+11
Thus, coefficient of xk in E
                                 = Coefficient of xk+1 in (1+x)n+11
                                  =n+1Ck+1

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