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Questions  

The coefficient of xn in the expansion of  (1+x)(1x)n, is 

a
(−1)n−1n
b
(−1)n(1−n)
c
(−1)n−1(n−1)2
d
(n−1)

detailed solution

Correct option is B

We have,Coefficient of xn in (1+x)(1−x)n=Coefficient of xn in (1−x)n+ Coefficient of xn−1 in (1−x)n=(−1)n nCn+(−1)n−1nCn−1=(−1)n(1−n)

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