Coefficient of x2n+t in the expansion of E=1(1+x)1+x21+x41+x8…1+x2n(where |x|<1) is

Multiplying the numerator and denominator of by 1 – x, we have G.E.=1-x(1-x)(1+x)1+x21+x4…1+x2n=1-x1-x21+x21+x4…1+x2n=1-x1-x41+x4…1+x2n=…=1-x1-x2n+1=(1-x)1-x2n+1-1=(1-x)1+x2n+1+x2n+2+…         since 1-x-n=1+x+x2+........∞,  where n∈N∴ Coefficient of x2n+t is 1