The coefficient of xr[0≤r≤(n−1)] in the expansion of (x+3)n−1+(x+3)n−2(x+2)+(x+3)n−3(x+2)2+⋯+(x+2)n−1 is
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a
nCr3r−2n
b
nCr3n−r−2n−r
c
nCr3r+2n−r
d
nc r3r-2n-r
answer is B.
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Detailed Solution
We have(x+3)n−1+(x+3)n−2(x+2)+(x+3)n−3(x+2)2+⋯+(x+2)n−1=(x+3)n−(x+2)n(x+3)−(x+2)=(x+3)n−(x+2)n ∵xn−anx−a=xn−1+xn−2a1+xn−3a2+⋯+an−1Therefore, coefficient of xr in the given expression is equal to coefficient of xr in [(x + 3)n - (x + 2)n], which is given by nCr3n−r−nCr2n−r=nCr3n−r−2n−r