The coefficient of x2y3 in the expansion of (1−x+y)20 is
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a
20!2!3!
b
−20!2!3!
c
20!5!2!3!
d
20!15!2!3!
answer is D.
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Detailed Solution
The general term in the expansion of (1−x+y)20 is20!r!s!t!1r(−x)s(y)t, where r+s+t=20For x2y3, r=15,s=1,t=3we have the term20!15!2!3!115(−x)2(y)3Hence, the coefficient of x2y3 is20!15!2!3!