First slide
Multinomial expansion
Question

The coefficient of x2y3 in the expansion of (1x+y)20 is

Easy
Solution

The general term in the expansion of (1x+y)20 is

20!r!s!t!1r(x)s(y)t, where r+s+t=20

For x2y3r=15,s=1,t=3we have the term

20!15!2!3!115(x)2(y)3

Hence, the coefficient of x2y3 is

20!15!2!3!

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