Questions
The coefficients of three consecutive terms of are in the ratio . Then,
a
5
b
7
c
6
d
8
detailed solution
Correct option is C
Let , rth,(r+1)th and (r+2)th be three consecutive terms in the expansion of (1+x)n+5It is given that n+5Cr−1:n+5Cr:n+5Cr+1=5:10:14⇒ n+5Cr 1+3Cr−1=105 and n+5Cr+1 n+5Cr=1410⇒n+5−r+1r=2 and n+5−rr+1=75 ⇒n−3r+6=0 and 5n−12r+18=0 ⇒n=6,r=4Talk to our academic expert!
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The coefficient of x7 in the expression is
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