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Q.

Coefficients of variation of two distributions are 50 and 60, and their arithmetic means are 30 and 25, respectively. Difference of their standard deviations is

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a

0

b

1

c

1.5

d

2.5

answer is A.

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Detailed Solution

Here, (CV)1=50,(CV)2=60,x¯1=30 and x¯2=25∴ (CV)1=σ1x1¯×100⇒50=σ130×100∴ σ1=30×50100=15 and CV2=σ2x2¯×100⇒ 60=σ225×100∴ σ2=60×25100=15 Now, σ1−σ2=15−15=0
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