A coin is tossed 7 times. Then the probability that at least 4 consecutive heads appear is
3/16
5/32
3/18
1/8
Let H denote the head, T the tail and ∗ any of the head or tail. Then, P(H)=1/2,P(T)=1/2 and P(∗)=1. For at least
four consecutive heads, we should have any of the following
patterns:
Since all the above cases are mutually exclusive, the probability of getting at least four consecutive heads (on adding) is1/16+3/32=5/32