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A coin is tossed 7 times. Then the probability that at least 4 consecutive heads appear is
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a
3/16
b
5/32
c
3/18
d
1/8
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Correct option is B
Let H denote the head, T the tail and ∗ any of the head or tail. Then, P(H)=1/2,P(T)=1/2 and P(∗)=1. For at least four consecutive heads, we should have any of the following patterns:Since all the above cases are mutually exclusive, the probability of getting at least four consecutive heads (on adding) is1/16+3/32=5/32Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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