A coin whose faces are marked 3 and 5 is tossed 4 times. The odds against the sum of the numbers thrown being less than 15 are
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a
11:5
b
5:11
c
11:16
d
5:16
answer is A.
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Detailed Solution
E<15 E¯≥15 (3 3 5 5) (5 5 5 3) (5 5 5 5) P(E¯)=4!2!2!+4!3!+116 =1116 P(E)=516 The odds against the sum of the numbers thrown being less than 15 are 11:5