In a competetion A, B and C are participating the probability that A wins in twice that of B. The probability that B wins in twice that of C. Then the probability that A loses in

Given that : P(A)=2P(B) , P(B)=2P(C) A∪B∪C = S, A∩B=B∩C=C∩A =ϕ       P(A)+P(B)+P(C) = 1 ⇒ 2P(B)+P(B)+P(C) = 1 ⇒ 3P(B)+P(C) = 1 ⇒ 6P(C)+P(C) = 1 ⇒P(C) = 17 ⇒P(B) = 27 & P(A) = 47 ∴ P(A¯) = 37