Complete set of range of the function $$f(x)=1x6+$$|x|$$3$$−$$1$$ is equal to

Correct option is 2−∞,−1∪0,∞

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$Complete set of range of the function f (x) = \frac{1}{x^{6} + | x |^{3} - 1} is equal to$

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−1,0

−∞,−1∪0,∞

−∞,−2∪0,∞

−∞,0∪1,∞

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detailed solution

Correct option is B

Given that f(x)=1x6+|x|3−1 Clearly x6+|x|3≥0⇒x6+|x|3−1≥−1 [ If x>a(a<0) then 1x∈(−∞,1a)∪(0,∞) So range of f(x)=(−∞,−1]∪(0,∞) . Therefore, the correct answer is (2).

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Complete set of range of the function f(x)=1x6+|x|3−1 is equal to

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$Complete set of range of the function f (x) = \frac{1}{x^{6} + | x |^{3} - 1} is equal to$