The complete solution set of the equation x2−5x+6+x2+12x+27=|17x+21| is

We have x2−5x+6+x2+12x+27=|17x+21|or x2−5x+6+x2+12x+27=x2+12x+27−x2−5x+6⇒ x2−5x+6x2+12x+27≤0⇒ (x−2)(x−3)(x+3)(x+9)≤0From the sign scheme, x∈[−9,−3]∪[2,3]