The complete solution set of the equation x2−5x+6+x2+12x+27=|17x+21| is
x∈[−9,3]
x∈[−3,2)∪(2,3]
x∈[−9,−3]∪[2,3]
x∈(−2,3)
We have x2−5x+6+x2+12x+27=|17x+21|
or x2−5x+6+x2+12x+27
=x2+12x+27−x2−5x+6
⇒ x2−5x+6x2+12x+27≤0⇒ (x−2)(x−3)(x+3)(x+9)≤0
From the sign scheme, x∈[−9,−3]∪[2,3]