The complex numbers sinx+icos2x and cosx−isin2x are conjugate to each other for
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a
x=nπ,n∈I
b
x=n+12π,n∈I
c
x=0
d
no value of x.
answer is D.
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Detailed Solution
sinx+icos2x¯=cosx−isin2x⇒ sinx−icos2x=cosx−isin2x⇒ sinx=cosx and cos2x=sin2x⇒ tanx=1 and tan2x=1These two equations cannot hold simultaneously.