Questions
The complex numbers satisfying are vertices of a triangle which is
a
of area zero
b
right-angled isosceles
c
equilateral
d
obtuse-angle isosceles
detailed solution
Correct option is C
z1−z3z2−z3=z1−z3z2−z3=1−i32=14(1+3)=1⇒ z1−z3=z2−z3Also, z1−z3z2−z3−1=1−i32−1→ z1−z2z2−z3=−1−i32⇒ z1−z2z2−z3=14(1+3)=1⇒ z1−z2=z2−z3Thus , z1−z3=z2−z3=z2−z1Hence, z1, z2 and z3 are the vertices of an equilateral triangle.Talk to our academic expert!
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The complex number z, satisfies the condition The maximum distance from the origin of coordinates to the point is
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