The complex numbers z1, z2 and z3 satisfying z1−z3z2−z3=12(1−3i) are vertices of a triangle which is
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a
of area zero
b
right-angled isosceles
c
equilateral
d
obtuse-angle isosceles
answer is C.
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Detailed Solution
z1−z3z2−z3=z1−z3z2−z3=1−i32=14(1+3)=1⇒ z1−z3=z2−z3Also, z1−z3z2−z3−1=1−i32−1→ z1−z2z2−z3=−1−i32⇒ z1−z2z2−z3=14(1+3)=1⇒ z1−z2=z2−z3Thus , z1−z3=z2−z3=z2−z1Hence, z1, z2 and z3 are the vertices of an equilateral triangle.