The condition that one root of the equation (1+m2)x2+2cmx+(c2−a2)=0 is reciprocal of the other is
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a
1+m2=c2−a2
b
1+m2+2c=0
c
c=a1+m2
d
1+m2=cm
answer is A.
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Detailed Solution
The given equation is (1+m2)x2+2mxc+(c2−a2)=0 let the roots of the equation α and 1α ∴ Product of the roots =α.1α=c2−a21+m2 ⇒1=(c2−a2)(1+m2) ⇒1+m2=c2−a2 Which is the required condition.