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The condition for the roots of the equation,
$(c^{2} - ab) x^{2} - 2 (a^{2} - bc) x + (b^{2} - ac) = 0$ to be equals

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a=0

b=0

c=0

None of these

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detailed solution

Correct option is A

According to question,4(a2-bc)2-4(c2-ab)(b2-ac)=0⇒a(a3+b3+c3-3abc)=0⇒a=0 or a3+b3+c3=3abc

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The condition for the roots of the equation,(c2-ab)x2-2(a2-bc)x+(b2-ac)=0 to be equals

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The condition for the roots of the equation,
$(c^{2} - ab) x^{2} - 2 (a^{2} - bc) x + (b^{2} - ac) = 0$ to be equals