The condition for the roots of the equation,
(c2-ab)x2-2(a2-bc)x+(b2-ac)=0 to be equals
a=0
b=0
c=0
None of these
According to question,
4(a2-bc)2-4(c2-ab)(b2-ac)=0
⇒a(a3+b3+c3-3abc)=0
⇒a=0 or a3+b3+c3=3abc