Consider any set of observations x1,x2,x3,…,x101. It is given that x1
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a
x1
b
x51
c
x1+x2+⋯+x101101
d
x50
answer is B.
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Detailed Solution
Mean deviation is minimum when it is considered about an item equidistant from the beginning and the end, i.e., the median. In this case, the median is 101+12 th, i.e., 51 st item, i.e., x51.