This is true for exactly 16 ordered pairs (a, b), 1 a a, b < 6, namely (1, 1), (1,2), (1, 3), (1,4), (1,5), (1, 6), (2,2), (2,3), (2,4), (2,5), (2,6), (3, 3), (3,4), (3, 6), and (4,6). Thus, the required probability is 16/36 = 4/9
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