Consider the following relations. R = {(x, y) | x, y are real numbers and x = wy for some rational number w} S=mn,pqm,n,p,q are integer such that n.q ≠ 0 and qm=pn}Statement-1: S is an equivalence relation but R is not an equivalence relation.Statement-2: R and S both are symmetric.
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for ST
b
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1
c
STATEMENT-1 is True, STATEMENT-2 is False
d
STATEMENT-1 is False, STATEMENT-2 is True
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Since (0, 1) ∈ R but (1, 0) ∈ R, R is not symmetric and hence is not an equivalence relation so statement-2 is false. Next, For the relation S,qm=pn⇒mn=pqThus mn,pq∈S⇒mn=pqwhich shows that S is reflexive and symmetricAgain , mn,pq∈S and pq,rs∈S⇒ mn=pq=rs ⇒mn,rs∈SThus S is transitive and hence S is an equivalence relation. So, statement 1 is true
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
Consider the following relations. R = {(x, y) | x, y are real numbers and x = wy for some rational number w} S=mn,pqm,n,p,q are integer such that n.q ≠ 0 and qm=pn}Statement-1: S is an equivalence relation but R is not an equivalence relation.Statement-2: R and S both are symmetric.