Q.
Consider the function f:R→R defined by .fx=2−sin1x x, x≠0 0 , x=0 Then f is:
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a
not monotonic on −∞,0 and 0,∞
b
Monotonic on −∞,0∪0,∞
c
monotonic on −∞,0
d
Monotonic on 0,∞
answer is A.
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Detailed Solution
f(x)=2x-xsin1x x>0-2x+xsin1x x<0f'(x)=2+1xcos1x-sin1x x>0-2-1xcos1x-1sin1x x<0f'(x)=>0x>0<0x<0The function is non monotonic in the interval −∞,0 & 0,∞
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