Consider a hyperbola H:x2-2y2=4 Let the tangent at a point P(4,6) meet the x- axis at Q and latus rectum at Rx1,y1,x1>0. If F is a focus of H which is nearer to the point P , then the area of ΔQFR is equal to:
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a
46−146−1
b
46
c
6−1
d
76−2
answer is D.
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Detailed Solution
Tangent at (4,6) is 2x-6y=2 Tangent meet x -axis at Q(1,0) and latus rectum at R6,26(6-1) Area =12×26(6-1)×(6-1)=76-2