Q.

Consider 3 non-collinear points A(9,3), B(7,−1), and C(1,−1). Let P(a, b) be the centre and R is the radius of circle ‘S’ passing through points A,B,C. Also H(x¯,y¯) are the coordinates of the orthocentre of triangle ABC whose area be denoted by ∆. If D,E and F are the middle points BC, CA and AB respectively then the area of the triangle DEF is The value of a+b+R equalsThe order pair (x¯,y¯) is

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a

12

b

6

c

4

d

3

e

3

f

12

g

13

h

None of these

i

(9,6)

j

(9,-6)

k

(9,-5)

l

(9,5)

answer is , , .

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Detailed Solution

∆DEF=14 area of ABCEquation of perpendicular bisector of AC is ⇒y+2x=11Perpendicular bisector of BC is x  =4Solving altitudes through A & B we get (9, -5)
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