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Consider an A.P.a1,a2,a3, such that a3+a5+a8=11 and a4+a2=2 then the value of a1+a6+a7 is 

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a
-8
b
5
c
7
d
9

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detailed solution

Correct option is C

Given that a7+a5+a8=11⇒a+2d+a+4d+a+7d=11or      3a+13d=11                    (1)Given,a4+a2=−2⇒a+3d+a+d=−2or           a=−1−2d               (2)Putting value of a from (2) in (1), we get3(−1−2d)+13d=11⇒7d=14⇒d=2 and a=−5⇒a1+a6+a7=7


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