Consider an A.P a1,a2,a3,…… such that a3+a5+a8=11 and a4+a2=−2 then the value of a1+a6+a7 is
a+2d+a+4d+a+7d=11⇒3a+13d=11→ (1)
⇒a+3d+a+d=−2⇒a+2d=−1→2 From (1) and (2) ⇒d=2, a=-5
∴a1+a6+a7=3a+11d=7