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 Consider an A.P a1,a2,a3,.. such that a3+a5+a8=11 and a4+a2=2, then 

 the value of a1+a6+a7, is 

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a
-8
b
5
c
7
d
9

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detailed solution

Correct option is C

Given that a3+a5+a8=11⇒a+2d+a+4d+a+7d=11⇒3a+13d=11 Given a4+a2=−2⇒a+3d+a+d=−2⇒a=−1−2dPutting value of ‘a’ from (2) in (1), we get3(−1−2d)+13d=11⇒7d=14⇒d=2 and a=−5⇒a1+a6+a7=7


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