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 Consider an A.P, a1,a2,a3 such that a3+a5+a8=11, and a4+a2=2 then the  value of a1+a6+a7 is 

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a
-8
b
5
c
7
d
9

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detailed solution

Correct option is C

a3+a5+a8=11→3a+13d=11−−−1  n'th term in A.P =a+n-1da4+a2=−2⇒2a+4d=−2a=−1−2d−−−21 and 2⇒d=2,a=−5∴a1+a6+a7=3a+11d=7


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