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Q.

Consider an A.P, a1,a2,a3… such that a3+a5+a8=11, and a4+a2=−2 then the value of a1+a6+a7 is

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a

-8

b

5

c

7

d

9

answer is C.

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Detailed Solution

a3+a5+a8=11→3a+13d=11−−−1 n'th term in A.P =a+n-1da4+a2=−2⇒2a+4d=−2a=−1−2d−−−21 and 2⇒d=2,a=−5∴a1+a6+a7=3a+11d=7

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