Consider the planes 3x-6y+22+5=0 and 4x-12y+32=3.Theplane 67x-162y+47z+44=0 bisects the angle between the given planes which
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a
contains origin
b
is acute
c
is obtuse
d
none of these
answer is A.
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Detailed Solution
3x-6y+22+5=0-------- (i) -4x+12y-32+3=0 --------(ii)Bisector 3x−6y+2z+59+36+4=±−4x+12y−3z+316+144+9The plane which bisects the angle between the planes that contains the origin. 13(3x -6y+22 + 5) =7 (4x+ 12y-3z + 3) 67x - 162y + 47z + 44=0 ----------(iii)Further, 3 x (-4) + (-6) (12) + 2 x (-3) < 0 Hence, the origin lies in the acute angle.