Consider the point A ≡ (0, 1) and B ≡ (2, 0). Let P be a point on the line 4x + 3y + 9 = 0. Coordinates of the point P such that |PA – PB| is maximum, are

We have, |PA – PB | ≤ AB.Thus, for |PA – PB| to be maximum, point A, B and P must be collinear. The equation of line AB is x + 2y = 2Solving it with the given line, we get P = -845,135