Consider the points A0,1 and B2,0 and P be a point on the line 4x+3y+9=0. Then coordinates of P such that PA−PB is maximum are
−12/5, 17/5
−24/5, 17/5
−6/5, 17/5
0,−3
The equation of AB is
y−1=0−12−1x or x+2y−2=0
PA−PB≤AB
Thus, PA−PB is maximum if the points A,B, and P are collinear.
Hence, solving x+2y−2=0 and 4x+3y+9=0, we get point P≡−24/5, 17/5.