Consider the points A(0,1) and B(2,0), and P be a point on the line 4x+3y+9=0 . The coordinates of P such that |PA−PB| is maximum are
−125,175
−845,135
−65,175
0,-3
The equation of AB is x2+y1=1
or x+2y−2=0
|PA−PB|≤AB
the points l, B, and P are collinear
Hence, solving x+2y−2=0 and 4x+3y+9=0, we get point P≡−845,135