Consider the points A(0,1) and B(2,0), and P be a point  on the line 4x+3y+9=0 . The coordinates of P such that |PA−PB| is maximum are

The equation of AB is x2+y1=1 or  x+2y−2=0|PA−PB|≤AB the points l, B, and P are collinear Hence, solving x+2y−2=0 and 4x+3y+9=0, we get point P≡−845,135