Consider the set A of all determinants of order 3 with entries 0 or 1 only. Let B be the subset of A consisting of all determinants with value 1. Let C be the subset of A consisting of all determinants with value –1. Then:
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a
C is empty
b
B has as many elements as C
c
A=B∪C
d
B has twice as many elements as C
answer is B.
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Detailed Solution
Each member in B gives rise to a member in C which is obtained by interchanging two rows. Similarly each member in C gives rise to a member in B which is obtained by interchanging two rows. ⇒there is a one-one correspondance between the members of B and C. ⇒B has as many elements as C.