Questions
Consider a set P containing n elements. A subset A of P is drawn and there after set P is reconstructed. Now one
more subset B of P is drawn. Probability of drawing sets A and B so that has exactly one element is
detailed solution
Correct option is B
Let xi be any element of set P, we have following possibilities1 xi∈A,xi∈B2 xi∈A,xi∉B3 xi∉A,xi∈B4 xi∉A,xi∉BClearly, the element A o B it it belongs to A and B both.Thus out of these 4 ways only first way is favorable. Now the element that we want to be in the intersection can be chosenin'n' different ways. Hence required probability is n⋅(3/4)n−1Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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