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Consider the system of equations, x+ay=0,y+az=0,z+ax=0.Then the set of all values of a for which the system has a unique solution is 

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a
R−{1}
b
R−{-1}
c
{1,−1}
d
{1,0,−1}

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detailed solution

Correct option is B

The system of equations have a unique solution⇒1a001aa01≠0, Apply: C1→C1+C2+C3⇒(1+a)1a011a101≠0⇒(1+a)1-a+a2≠0⇒a3+1≠0⇒a3≠-1⇒a≠-1⇒a∈R-{-1}


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