Q.

The constant ‘c’ of Rolle’s theorem for the function f(x)=sinx  in [0,2π]  is

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a

π6

b

π3

c

π4

d

π2

answer is D.

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Detailed Solution

f1(x)=cosx  and f(0)=f(2π)=0                 c∈(0,2π)  such that f'(c)=0⇒cosc=0⇒c=π2   or 3π2
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