Download the app

Questions  

For a continuous function f, the value 0fxn+xnlogxx+11+x2dx is

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
π2
b
0
c
d

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is A

Putting 1x=t⇒dx=−1t2dt, soI=∫0∞ fxn+x−nlog⁡xdxx=−∫∞0 ft−n+tnlog⁡1ttdtt2=−∫0∞ ft−n+tnlog⁡tdtt=−I⇒   2I=0⇒I=0The given integral is equal to ∫0∞ 11+x2dx=tan−1⁡x0∞=π2


Similar Questions

ab(xa)(bx)dx(b>a) is equal to


whats app icon
phone icon