First slide

Introduction to mathematical reasoning

Question

Converse of the statement : If $x^{2}$ is odd then x is odd is

Easy

A

If $x^{2}$ is even then x is even
B

if x is odd then $x^{2}$ is odd
C

if x is odd then $x^{2}$ is even
D

if x is even then $x^{2}$ is odd

Solution

$c o n v e r s e o f p \to q i s q \to p$

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