The coordinates of the point on the circle x2+y2−2x−4y−11=0  farthest from the origin are

Given circle is x2+y2−2x−4y−11=0  and point O(0,0), C(1,2), r=4 Slope of CD=2 ⇒m=tanθ=2⇒cosθ=15, sinθ=25 Points A  and B  lie at distance of 4 units from C =(x1±45, 2±4(25)) =(1±45, 2±85) ∴ Farthest point is (1+45, 2+85)